2x^2-1x=190

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Solution for 2x^2-1x=190 equation:



2x^2-1x=190
We move all terms to the left:
2x^2-1x-(190)=0
a = 2; b = -1; c = -190;
Δ = b2-4ac
Δ = -12-4·2·(-190)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-39}{2*2}=\frac{-38}{4} =-9+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+39}{2*2}=\frac{40}{4} =10 $

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